he rellenado I have completed the application. he cumplido I have completed my sentence and I am a free man.He cumplido mi sentencia y soy un hombre libre. If (enteredNumberStr.size() = 0) return 0 īUG 4: all the '4' in the loops (lines 54 and 75) must be replaced withĮnteredNumberStr.size(), because the string becomes shorter during the code.īUG 5: enteredNumberStr, which contains the remaining numbers to check, must not modified at lines 35 and 77: use a temporary std::string instead. he terminado I have completed all of my homework. At the end of both loops you must compact the spaces:ĮnteredNumberStr.erase(std::remove(enteredNumberStr.begin(), enteredNumberStr.end(), ' '),enteredNumberStr.end()) Īnd you must return if all the 4 numbers have been replaced (else following code will trap): Here, when detecting greens, and in the previous loop which detects reds. This is my completed task 7 below: Can you show me the Java code for task 8 that will work with my code when I run it, thank you. Saying ‘please find attached’ may seem a bit old-fashioned, and the verb ‘find’ does not convey the exact meaning required. This is my JAVA code so far, I have completed Tasks 1-7 but not task 8. Robin’s box was beautiful a mattress in shape for a doll princess. Two decades ago, when my son was in kindergarten, I experienced to re-orient myself with all of the classes I uncovered about quite a few decades as an in-property tutor and homework coach. If your resume is required, the employer will ask for it. This is not the 1st time I have completed this. Usually, such forms list their complete requirements, including the documents that must be attached. ![]() I suggest to avoid of changing the string size but just replace the numbers with spaces: enteredNumberStr = ' ' Your application is a formal request to be considered for a job. I suggest to initialize "enteredNumberStr" at the beginning, and to remove the already tagged digits also in the first loop, not only in the second.ĮnteredNumberStr.erase(enteredNumberStr.begin() + counter2) īut enteredNumberStr becomes shorter at every loop, so the position (+counter2) is wrong and can furthermore produce traps. ![]() BUG 1: line 51: enteredNumberStr=std::to_string(enteredNumberInt) īut enteredNumberInt has been broken by the "while" loop at line 21īUG 2: numbers tagged as red: must be removed from enteredNumberStr, else they will be presented again at third loop (the one detecting yellows) and will be tagged as yellow too.
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